330=-16t^2+14t+382

Solution for 330=-16t^2+14t+382 equation:

330=-16t^2+14t+382

We move all terms to the left:

330-(-16t^2+14t+382)=0

We get rid of parentheses

16t^2-14t-382+330=0

We add all the numbers together, and all the variables

16t^2-14t-52=0

a = 16; b = -14; c = -52;
Δ = b2-4ac
Δ = -142-4·16·(-52)
Δ = 3524
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3524}=\sqrt{4*881}=\sqrt{4}*\sqrt{881}=2\sqrt{881}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{881}}{2*16}=\frac{14-2\sqrt{881}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{881}}{2*16}=\frac{14+2\sqrt{881}}{32}
$